MCQ
A particle is projected upwards. The times corresponding to height $h$ while ascending and while descending are $t‌‌_1$ and $t_2$ respectively. The velocity of projection will be
  • A
    $g{t_1}$
  • B
    $g{t_2}$
  • C
    $g\;\left( {{t_1} + {t_2}} \right)$
  • $\frac{{g\left( {{t_1} + {t_2}} \right)}}{2}$

Answer

Correct option: D.
$\frac{{g\left( {{t_1} + {t_2}} \right)}}{2}$
d
(d) If ${t_1}$ and ${t_2}$ are time of ascent and descent respectively then time of flight $T = {t_1} + {t_2} = \frac{{2u}}{g}$

==> $u = \frac{{g({t_1} + {t_2})}}{2}$

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