Question
A particle is projected with a speed u at an angle $\theta$ with the horizontal. Consider a small part of its path near the highest position and take it approximately to be a circular arc. What is the radius of this circle? This radius is called the radius of curvature of the curve at the point.

Answer


Particle is projected with speed ‘u’ at an angle $\theta.$ At the highest pt. the vertical component of velocity is‘0’.

So, at that point, velocity $=\text{u}\sin\theta$

centripetal force $=\text{mu}^2\cos^2\Big(\frac{\theta}{\text{r}}\Big)$

At highest pt.

$\text{mg}=\frac{\text{mv}^2}{\text{r}}$

$\Rightarrow\text{r}=\frac{\text{u}^2\cos^2\theta}{\text{g}}$

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