$\omega^2=100 \quad \omega=10$
$\omega A =4$ $\quad A=\frac{4}{10}=0.4\,m$
$A =40\,cm$
If the position and velocity of the particle at $t=0\, {s}$ are $2\, {cm}$ and $2\, \omega \,{cm} \,{s}^{-1}$ respectively, then its amplitude is $x \sqrt{2} \,{cm}$ where the value of $x$ is ..... .



Find time after which to the energy will become half of initial maximum value in damped force oscillation.

