A simple pendulum hangs from the ceiling of a car. If the car accelerates with a uniform acceleration, the frequency of the simple pendulum will
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(a) In this case frequency of oscillation is given by
$n = \frac{1}{{2\pi }}\sqrt {\frac{{\sqrt {{g^2} + {a^2}} }}{l}} $ where $a$ is the acceleration of car. If $ a$ increases then $n$ also increases.
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