A simple pendulum is suspended from the roof of a trolley which moves in a horizontal direction with an acceleration $a$, then the time period is given by $T = 2\pi \sqrt {\frac{l}{{g'}}} $, where $g'$ is equal to
A$g$
B$g - a$
C$g + a$
D$\sqrt {{g^2} + {a^2}} $
AIPMT 1991, Medium
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D$\sqrt {{g^2} + {a^2}} $
d (d)$g' = \sqrt {{g^2} + {a^2}} $
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