A simple pendulum with a bob of mass $‘m’$ oscillates from $A$ to $ C$ and back to $A$ such that $PB$ is $H.$ If the acceleration due to gravity is $‘g’$, then the velocity of the bob as it passes through $B$ is
  • A$mgH$
  • B$\sqrt {2gH} $
  • C$\sqrt {gH} $
  • D
    Zero
AIPMT 1995, Medium
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