A smooth sphere A is moving on a frictionless horizontal plane wi… - Vidyadip

MCQ

A smooth sphere $A$ is moving on a frictionless horizontal plane with angular speed $\omega $ and center of mass with velocity $v$. It collides elastically and head-on with an identical sphere $B$ at rest. Neglect friction everywhere. After the collision, their angular speeds are ${\omega _A}$ and ${\omega _B}$ respectively. Then

A
${\omega _A} < {\omega _B}$
B
${\omega _A} = {\omega _B}$
✓
${\omega _A} = \omega $
D
$\omega = {\omega _B}$

✓

Answer

Correct option: C.

${\omega _A} = \omega $

c
As the spheres are smooth there will be no friction (no torque) and therefore there will be no transfer of angular momentum. Thus $\mathrm{A}$, after collision will remain with its intial angular momentum $i . e ., \omega_{A}=\omega$

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