A wire is broken in four equal parts. A packet is formed by keeping the four wires together. The resistance of the packet in comparison to the resistance of the wire will be
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Let the resistance of the wire be $R$, then we know that resistance is proportional to the length of the wire. So each of the four wires will have $R/4$ resistance and they are connected in parallel. So the effective resistance will be
$\frac{1}{{{R_1}}} = \left( {\frac{4}{R}} \right)4 \Rightarrow {R_1} = \frac{R}{{16}}$
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