MCQ
Acetamide reacts with $P_2O_5$ to give
  • Methyl cyanide
  • B
    Methyl cyanate
  • C
    Ethyl cyanide
  • D
    Acetamide

Answer

Correct option: A.
Methyl cyanide
a
$C{H_3}CON{H_2}\xrightarrow{{{P_2}{O_5}}}C{H_3} - C \equiv N + {H_2}O$

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Reason $(R)$ : The partially bonded unhybridized p-orbital that develops in the trigonal bipyramidal transition state is stabilized by conjugation with the phenyl ring.

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