An electrical bulb rated $220\,V , 100\,W$, is connected in series with another bulb rated $220\,V$, $60\,W$.If the voltage across combination is $220\,V$, the power consumed by the $100\,W$ bulb will be about $........... W$
JEE MAIN 2022, Medium
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$R _{1}=\frac{ V ^{2}}{ P }=\frac{220^{2}}{100}=484$
$R _{2}=\frac{ V ^{2}}{ P }=\frac{220^{2}}{60}=484\left(\frac{10}{6}\right)$
$I =\frac{220}{484+484 \times \frac{10}{6}}$
$P _{1}= I ^{2} R _{1}=14.06\,W$
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