- A$0.635 $ methanol, $ 0.365$ ethanol
- ✓$0.365$ methanol, $0.635 $ ethanol
- C$0.574 $ methanol, $0.326 $ ethanol
- D$0.173 $ methanol, $0.827 $ ethanol
Partial pressure of ethanol $=4.556 \,kPa$
Total pressure $=$ Partial pressure of methanol $+$ Partial pressure of ethanol
Total pressure $=2.619+4.556=7.175\, kPa$
$X _{\text {methanol: }}$ : Mole fraction of methanol
$X _{\text {ethanol: }}$ : Mole fraction of ethanol
The partial pressure of methanol $= X _{\text {methanol }} \times$ Total pressure
$\therefore X _{\text {methanol }}=\frac{2.619}{7.175}$
$=0.365$
$\therefore$ Mole fraction of ethanol $= 1 -$ Mole fraction of methanol
$=1-0.365$
$=0.635$
Hence, the correct option is $B$.
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Assertion $A$ : Thin layer chromatography is an adsorption chromatography.
Reason $R$: A thin layer of silica gel is spread over a glass plate of suitable size in thin layer chromatography which acts as an adsorbent. In the light of the above statements, choose the correct answer from the options given below.
$(i)\, [Co(en)_2(Ox)]^+$
$(ii)\, [Fe(Trien)(Ox)]^+$
$(iii)\, [Ca(EDTA)]^{-2}$
$(iv)\, [Pt(Ox)_2 (H_2O)_2]$
