MCQ
An object is placed first at infinity and then at $20 \mathrm{~cm}$ from the object side focal plane of the convex lens. The two images thus formed are $5 \mathrm{~cm}$ apart. The focal length of the lens is
  • A
    $5 \mathrm{~cm}$
  • $10 \mathrm{~cm}$
  • C
    $15 \mathrm{~cm}$
  • D
    $20 \mathrm{~cm}$

Answer

Correct option: B.
$10 \mathrm{~cm}$
For first case : $\frac{1}{f}=\frac{1}{v}-\frac{1}{\infty} \Rightarrow f=v$
For second case $\frac{1}{f}=\frac{1}{(f+5)}-\frac{1}{-(f+20)} \Rightarrow f=10 \mathrm{~cm}$
Alternative sol. $-f^2=x_1 x_2 \Rightarrow f=10 \mathrm{~cm}$.

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