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As shown in the figure, a network of resistors is connected to a battery of $2\,V$ with an internal resistance of $3\,\Omega$. The currents through the resistors $R_4$ and $R_5$ are $I_4$ and $I_5$ respectively. The values of $I_4$ and $I_5$ are :
  • A$I _4=\frac{8}{5} A$ and $I _5=\frac{2}{5}\,A$
  • B$I _4=\frac{24}{5} A$ and $I _5=\frac{6}{5}\,A$
  • C$I _4=\frac{6}{5} A$ and $I _5=\frac{24}{5}\,A$
  • D$I _4=\frac{2}{5} A$ and $I _5=\frac{8}{5}\,A$
JEE MAIN 2023, Diffcult
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