MCQ
Atomic number of an element is $26.$ The element shows
  • Ferromagnetism
  • B
    Diamagnetism
  • C
    Paramagnetism
  • D
    None of these

Answer

Correct option: A.
Ferromagnetism
(a) Element with atomic number $26$ is $Fe.$

It is a ferromagnetic.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

The equivalent weight of a metal is $9$ and vapour density of its chloride is $59.25$. The atomic weight of metal is
Select the incorrect statement

$(a)$ $PCl_5$ form weak monobasic acid during hydrolysis
$(b)$ In $B_3N_3H_6$ nucleophile attack on $B-$ atom
$(c)$ $Al_2Cl_6$ is a polar and planar molecule
$(d)$ In $AlF_3$, hybridisation of $Al$ is $sp^2$

For a good quality cement, the ratio of silica to alumina is found to be
The wave function $\psi_{n / m m}$ is a mathematical function whose value depends upon spherical polar coordinates $(r, \theta, \phi)$ of the electron and characterized by the quantum numbers $n, l$ and $m_l$. Here $r$ is distance from nucleus, $\theta$ is colatitude and $\phi$ is azimuth. In the mathematical functions given in the Table, $\mathrm{Z}$ is atomic number and $a_0$ is Bohr radius.

$column 1$ $column 2$ $column 3$
$(I)$ $1$s orbital $(i)$ $\psi_{n, l, m_l} \propto\left(\frac{Z}{a_0}\right)^{\frac{3}{2}} e^{-\left(\frac{Z r}{a_0}\right)}$ $image$
($II$) $2 \mathrm{~s}$ orbital $(ii)$ One radial node $(Q)$ Probability density at nucleus $\propto \frac{1}{a_0^3}$
$(III)$ $2 p_z$ orbital $(iii)$ $\psi_{n, l m_l} \propto\left(\frac{Z}{a_0}\right)^{\frac{5}{2}} r e^{-\left(\frac{Z r}{2 a_0}\right)} \cos \theta$ $(R)$ Probability density is maximum at nucleus
$(IV)$ $3 \mathrm{~d}_{\mathrm{z}}^2$ orbital $(iv)$ $x y$-plane is a nodal plane $(S)$ Energy needed to excite electron from $n=2$ state to $n=4$ state is $\frac{27}{32}$ times the energy needed to excite electron from $n=2$ state to $n=6$ state

($1$) For the given orbital in Column $1$, the only $CORRECT$ combination for any hydrogen-like species is

$[A] (IV) (iv) (R)$   $[B] (II) (ii) (P)$    $[C] (III) (iii) (P)$    $[D] (I) (ii) (S)$

($2$)  For $\mathrm{He}^{+}$ion, the only INCORRECT combination is

$[A] (II) (ii) (Q)$ $[B] (I) (i) (S)$ $[C] (I) (i) (R)$ $[D] (I) (iii) (R)$

($3$) For hydrogen atom, the only $CORRECT$ combination is

$[A] (I) (iv) (R)$   $[B] (I) (i) (P)$    $[C] (II) (i) (Q)$   $[D] (I) (i) (S)$

Give the answer quetion ($1$) ($2$) and ($3$)

Palmitic acid is
$4d^3\,5s^2$  configuration belong to which group
Choose the correct option($s$) that give($s$) an aromatic compound as the major product.
The electronegativity of $C,\,\,H,\,\,O,\,\,N$ and $S$ are $2.5$, $2.1$, $3.5$, $3.0$ and $2.5$ respectively. Which of the following bond is most polar
Phenol on distillation with zinc dust gives
Solid $NaCl$ is a bad conductor of electricity since