MCQ
Boron form covalent compound due to
- ASmall size
- BHigher ionization energy
- CLower ionization energy
- ✓Both $(a)$ and $(b)$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
[Atomic number, $\mathrm{Cr}=24, \mathrm{Mn}=25, \mathrm{Fe}=26, \mathrm{Co}=27$ ]

$A$. A liquid evaporates to vapour.
$B$. Temperature of a crystalline solid lowered from $130 \mathrm{~K}$ to $0 \mathrm{~K}$.
$C$. $2 \mathrm{NaHCO}_{3(\mathrm{~s})} \rightarrow \mathrm{Na}_2 \mathrm{CO}_{3(\mathrm{~s})}+\mathrm{CO}_{2(\mathrm{~g})}+\mathrm{H}_2 \mathrm{O}_{(\mathrm{g})}$
$D$. $\mathrm{Cl}_{2(g)} \rightarrow 2 \mathrm{Cl}_{(g)}$
Choose the correct answer from the options given below:
Given : $1 \,F =96500\, C \,mol ^{-1}$
Atomic mass of $Fe =56\, g \,mol ^{-1}$