MCQ
Carbylamine reaction is given by
- ✓${1^o}$ amine
- B${3^o}$ amine
- C${2^o}$ amine
- DQuarternary salts
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$A\xrightarrow{{{\text{Reduction}}}}B\xrightarrow{{HN{O_2}}}{C_2}{H_5}OH$

$(A)$ Reduction of $HCHO$
$(B)$ Oxidation of $HCHO$
$(C)$ Reduction of $PhCHO$
$(D)$ Oxidation of $Ph-CHO$
