MCQ
$Ce-58 $ is a member of
- A$s-$ block
- B$p-$ block
- C$d-$ block
- ✓$f-$ block
✓
Answer
Correct option: D.
$f-$ block
d
(d) $Ce - 58$ have configuration $1{s^2},2{s^2}2{p^6},3{s^2}3{p^6}3{d^{10}},$ $4{s^2}4{p^6}4{d^{10}}4{f^2},5{s^2}5{p^6}5{d^0},6{s^2}$
(d) $Ce - 58$ have configuration $1{s^2},2{s^2}2{p^6},3{s^2}3{p^6}3{d^{10}},$ $4{s^2}4{p^6}4{d^{10}}4{f^2},5{s^2}5{p^6}5{d^0},6{s^2}$
Since, its last electron enter in $f- $ sub-shell, therefore it is a member of $f-$ block.
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