If A and B are two independent events with $\text{P}(\text{A})=\frac{3}{5}$ and $\text{P}(\text{A})=\frac{4}{9},$ then $\text{P}(\text{A'}\cap\text{B'})$ equals:
- $\frac{4}{15}$
- $\frac{8}{45}$
- $\frac{1}{3}$
- $\frac{2}{9}$
Solution:
Since A and B are independent events, A' And B' are aslo independent.
$\therefore\text{P}(\text{A}'\cap\text{B}')=\text{P}(\text{A})\cdot\text{P}(\text{B})$
$=\big[1-\text{P}(\text{A})\big]\big[1-\text{P}(\text{B})\big]$
$=\Big(1-\frac{3}{5}\Big)\Big(1-\frac{4}{9}\Big)$
$=\frac{2}{5}\cdot\frac{5}{9}=\frac{2}{9}$
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Which of the following is the general solution of $\frac{\text{d}^2\text{y}}{\text{d}\text{x}^2}-2\frac{\text{d}\text{y}}{\text{d}\text{x}}+\text{y}=0?$
$\text{y}=(\text{Ax}+\text{B})\text{e}^{\text{x}}$
$\text{y}=(\text{Ax}+\text{B})\text{e}^{-\text{x}}$
$\text{y}=\text{Ax}\text{e}^{\text{x}}+\text{B}\text{e}^{\text{x}}$
$\text{y}=\text{A}\cos\text{x}+\text{B}\sin\text{x}$