Considering the following circuit, select the correct alternative
Medium
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Current won't pass through
$4\, \Omega $ and $ 6\, \Omega$
so $\mathrm{P}=\frac{(30)^{2}}{3}=300 \mathrm{\,W}$
$I=\frac{30}{3}=10 \mathrm{\,A}$
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