A cylindrical resistance is connected across battery $\varepsilon $ . Cylinder has uniform free electron density, mid part of cylinder has larger radius as shown in figure. Then $V_d$ (drift velocity) $V/S$ (distance across the length of the resistance)
A
B
C
D
Medium
Download our app for free and get started
A
a $\mathrm{i}=\mathrm{JA}$
$\mathrm{J}=\mathrm{neVd}$
$\mathrm{i}=$ $\mathrm{Ane}$ $\mathrm{Vd}$
$\mathrm{i}=$ constant
$\mathrm{AVd}=$ Constant
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
The equivalent resistance between the points $P$ and $Q$ in the network given here is equal to ................ $\Omega$ (given $r = \frac{3}{2}\Omega $)
There is a current of $40$ ampere in a wire of ${10^{ - 6}}\,{m^2}$ area of cross-section. If the number of free electron per ${m^3}$ is ${10^{29}}$, then the drift velocity will be
Two resistances ${R_1}$ and ${R_2}$ when connected in series and parallel with $120\, V$ line, power consumed will be $25\, W$ and $100\, W$ respectively. Then the ratio of power consumed by ${R_1}$ to that consumed by ${R_2}$ will be
Ametallic conductor of irregular cross-section is as shown in the figure. Aconstant potential difference is applied across the ends $(1)$ and $(2)$. Then :
An electrical circuit consists of ten $100 \,\Omega$ resistors. Out of these $10$ resistors, a group of $n _1$ resistors are connected in parallel and another group of $n _2$ resistors are separately connected in parallel. These two groups are then connected in series and this combination is connected to a voltage source of $100 \,V$. If the net current though the circuit is $2.5 \,A$. The values of $n _1$ and $n _2$ are
A wire of $1 \,\Omega$ has a length of $1\, m$. It is stetched till its length increases by $25\, \%$. The percentage change in resistance to the neartest integer is .....$\%$