MCQ
$\frac{1}{{\tan 3A - \tan A}} - \frac{1}{{\cot 3A - \cot A}} = $
- A$\tan A$
- B$\tan 2A$
- C$\cot A$
- ✓$\cot 2A$
$=\frac{1}{{\tan 3A - \tan A}} + \frac{{\tan A\tan 3A}}{{\tan 3A - \tan A}}$
$= \frac{1}{{\tan 2A}} = \cot 2A$.
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