Download App

DETERMINANTS — Maths STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 ScienceMathsDETERMINANTS1 Mark
Question
Evaluate $\begin{bmatrix}\text{i}&-1\\-1&\text{i}\end{bmatrix}$
  1. 4
  2. 3
  3. 2
  4. 0
✓

Answer

  1. 0

Solution:

Expanding along $\text{R}_1,$ we get.

$\triangle=\text{-i}(\text{i})-(-1)(-1)=-\text{i}^2-1=-(-1)-1=0.$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from DETERMINANTS→DETERMINANTS — all question types→Maths STD 12 Science question papers→Gujarat Board STD 12 Science question papers→Gujarat Board question paper generator→

Similar questions

$\int_{}^{} {\frac{{{{({x^4} - x)}^{1/4}}}}{{{x^5}}}\;dx} $ is equal to
→
If $\vec{\text{r}}.\vec{\text{a}}=\vec{\text{r}}.\vec{\text{b}}=\vec{\text{r}}.\vec{\text{c}}=0$ for some non-zero vector $\vec{\text{r}},$ then the value of $\big[\vec{\text{a}}\vec{\text{ b }}\vec{\text{c}}\big],$ is:
  1. 2
  2. 3
  3. 0
  4. None of these
→
${d \over {dx}}\left[ {\log \left\{ {{e^x}{{\left( {{{x - 2} \over {x + 2}}} \right)}^{3/4}}} \right\}} \right]$ is equals to
→
Refer to Question 18 (Maximum value of Z+ Minimum value of Z) is equal to:
→
The equation of the plane passing through (2, −3, 1) and is normal to the line joining the points (3, 4, −1) and (2, −1, 5) is given by:
  1. x + 5y − 6z + 19 = 0
  2. x − 5y + 6z − 19 = 0
  3. x + 5y + 6z + 19 = 0
  4. x − 5y − 6z − 19 = 0
→
If $\vec a = 2\hat i + \hat j + \hat k,\vec b = \hat i + 2\vec j + 2\vec k,\vec c = \vec i + \vec j + 2\hat k$ and $\left( {1 + \alpha } \right)\hat i + \beta \left( {1 + \alpha } \right)\hat j + \gamma \left( {1 + \alpha } \right)\left( {1 + \beta } \right)\hat k = \hat a \times \left( {\vec b \times \vec c} \right)$ ,  then $\alpha ,\beta ,\gamma $ are
→
$\int\big(1+5\text{x}+10\text{x}^2+10\text{x}^3+5\text{x}^4+\text{x}^5\big)\text{dx}=\frac{(1+\text{x})\text{p}}{6}+\text{c}$ then p is:
  1. 5
  2. 6
  3. 7
  4. 8
→
The area of the ellipse $\frac{\text{x}2}{9}+\frac{\text{y}^2}{4}=1$ in first quadrant is $6\pi$ sq. units.
The ellipse is rotated about its centre in anti-clockwise direction till its major axis coincides with y-axis. Now the area of the ellipse in first Quadrant is $\pi$ sq. units.
  1. 2
  2. 4
  3. 6
  4. 8
→
Choose the correct answer from the given four options.

The order and degree of the differential equation $\Big[1+\Big(\frac{\text{dy}}{\text{dx}}\Big)^2\Big]=\frac{\text{d}^2\text{y}}{\text{d}\text{x}^2}$ are:

  1. $2,\frac{3}{2}$
  2. 2, 3
  3. 2, 1
  4. 3, 4
→
Choose the correct answer from the given four option.
The integrating factor of the differential equation $\frac{\text{d}\text{y}}{\text{d}\text{x}}+\text{y}=\frac{1+\text{y}}{\text{x}}$ is:
  1. $\frac{\text{x}}{\text{e}^{\text{x}}}$
  2. $\frac{\text{e}^{\text{x}}}{\text{x}}$
  3. ${\text{x}}\text{e}^{\text{x}}$
  4. $\text{e}^{\text{x}}$
→