Question
- Explain why an alkylamine is more basic than ammonia.
- How would you convert:
- Aniline to nitrobenzene.
- Aniline to iodobenzene?
✓
Answer
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| Column I (Example) |
| Column II (Reaction) |
(i) | $\ \ \ \ \ \ \ \ \ \ \ \ \ \text{O}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{O}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ || \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ||\\\text{CH}_3-\text{C}-\text{Cl}+\text{H}_2\xrightarrow{\text{Pd-C/BaSO}_4}\text{CH}_3-\text{C}-\text{H}$ | (a) | Friedel Crafts acylation |
(ii) |
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(iii) |
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(iv) | $\text{R}-\text{CH}_2-\text{COOH}\xrightarrow{\text{Br}_2/\text{Red}\ \text{P}}\text{R}-\text{CH}-\text{COOH}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ^\text{Br}$ | (d) | Cannizaro’s reaction |
(v) | $\text{CH}_3-\text{CN}\xrightarrow[\text{(ii)}\ \text{H}_2\text{O}/\text{H}^+]{\text{(i)}\ \text{SnCl}_2/\ \text{HCl}}\text{CH}_3\text{CHO}$ | (e) | Rosenmund’s reduction |
(vi) | $2\text{CH}_3\text{CHO}\xrightarrow{\text{NaOH}}\text{CH}_3-\text{CH}=\text{CH}=\text{CHCHO}$ | (f) | Stephen’s reaction |
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