Question
Find whether $(\sqrt{2},4\sqrt{2})$ is the solution of the equation x – 2y = 4 or not?
✓
Answer
x-2y=4
Put x = $ \sqrt{2}$ , y = $4 \sqrt{2}$ in given equation, we get
$\sqrt{2}-2(4\sqrt{2})=\sqrt{2}-8\sqrt{2}=-7\sqrt{2}$
which is not 4.
∴ $(\sqrt2,4\sqrt2)$ is not a solution of given equation.
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