- AElectrophilic substitution
- BNucleophilic substitution
- ✓Free-radical substitution
- DOxidation
Under photochemical conditions, the halogens will break homolytically and forms radical. The halogen radical will abstract hydrogen from alkanes. Now the alkyl radical can combine with alkyl radical or it can also combine with halogen radical forming alkyl radicals.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Reason $(R)$ : Oxygen forms $\mathrm{p} \pi-\mathrm{p} \pi$ multiple bonds with itself and other elements having small size and high electronegativity like $\mathrm{C}, \mathrm{N}$, which is not possible for sulphur.
In the light of the above statements, choose the most appropriate answer from the options given below :

| List$-I$ | List$-II$ | ||
| $(a)$ | Sucrose | $(i)$ |
$\beta$ -D-Galactose and $\beta$ -D-Glucose |
| $(b)$ | Lactose | $(ii)$ | $\alpha$ -D-Glucose and $\beta$ -D-Fructose |
| $(c)$ | Maltose | $(iii)$ | $\alpha$ -D-Glucose and $\alpha$ -D-Glucose |
Choose the correct answer from the options given below: