MCQ
If $(a -2)x^2 + ay^2 = 4$ represents rectangular hyperbola, then $a$ equals :-
- A$0$
- B$2$
- ✓$1$
- D$3$
$\Rightarrow$ On simplifying Equation
1, $\frac{x^{2}}{\frac{4}{a-2}}-\frac{y^{2}}{\left(\frac{-4}{a}\right)}=1$
where we see, $a^{2}=\frac{4}{a-2}$ and $b^{2}=\frac{-4}{a}$
If $b^{\prime}=a^{\prime} \Rightarrow b^{\prime 2}=a^{\prime 2}$
$\Rightarrow \frac{-4}{a}=\frac{4}{a-2}$
$\Rightarrow-(a-2)=a$
$\Rightarrow 2=2 a$
$\Rightarrow a=1$
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$P:\left|z_2-z_1\right|+\left|z_3-z_2\right|+\ldots+\left|z_{10}-z_9\right|+\left|z_1-z_{10}\right| \leq 2 \pi$
$Q:\left|z_2^2-z_1^2\right|+\left|z_3^2-z_2^2\right|+\ldots .+\left|z_{10}^2-z_9^2\right|+\left|z_1^2-z_{10}^2\right| \leq 4 \pi$
Then,