If an electric heater is rated at $1000\, W$, then the time required to heat one litre of water from $20\,^oC$ to $60\,^oC$ is
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Heat required to heat $1$ $\mathrm{Lt}$
water $=m s \Delta \theta$
$=1 \times 4200 \times(60-20)$
$=4200 \times 40$
requred time $=\frac{4200 \times 40}{1000}$
$=42 \times 4=168$
i.e. $2$ $\mathrm{min}$ $48$ $\mathrm{second}$
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