If in the circuit, power dissipation is $150\, W$, then $R$ is ............... $\Omega$
AIEEE 2002, Medium
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(b) $P = \frac{{{V^2}}}{{{R_{eq}}}} \Rightarrow 150 = \frac{{{{(15)}^2}}}{{[2R/(R + 2)]}} = \frac{{225 \times (R + 2)}}{{2R}}$
$ \Rightarrow $ $R = \frac{{450}}{{75}} = 6\,\Omega $.
$ \Rightarrow $ $R = \frac{{450}}{{75}} = 6\,\Omega $.
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