If the time period of a two meter long simple pendulum is $2\, s$, the acceleration due to gravity at the place where pendulum is executing $S.H.M.$ is
JEE MAIN 2021, Medium
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$T =2 \pi \sqrt{\frac{l}{ g }}$

$2=2 \pi \sqrt{\frac{2}{ g }}$

$\Rightarrow g =2 \pi^{2}$

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