MCQ
In a common emitter transistor circuit, the base current is $40 \,\mu A$, then $V_{B E}$ is .......... $V$
- A$2$
- ✓$0.2$
- C$0.8$
- D$0$
✓
Answer
Correct option: B.
$0.2$
b
(b)
(b)
Applying kirchoff
$10-245 \times 40 \times 10^{-3}=V_{B E}$
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