MCQ
In isothermal, isobaric and adiabatic processes, the value of work done for equal volume change is minimum:
- AIsothermal
- BIsobaric
- ✓Adiabatic
- DNone of these
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$\text{v}_1=\text{v}_2$
$\text{v}_1=13.6\text{v}_2$
$\text{v}_1=\frac{\text{v}_2}{\text{13.6}\cdot}$
$\text{v}_1=\sqrt{13.6}\text{v}_2$
