MCQ
In the Boolean algebra, the following one is wrong:
  • A
    1.0 = 0
  • B
    0.1 = 0
  • C
    1.1 = 0
  • D
    1.1 = 1

Answer

  1. 1.1 = 0

Explanation:

In the Boolean algebra,

1.0 = 0

0.1 = 0

1.1 = 1

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

It becomes possible to define potential at a point in an electric field because electric field:
The penetrating power of X-rays depends upon :

If a rod has resistance 4 W and if rod is turned as half cycle then the resistance along diameter

(a) 1.56 W

(b) 2.44 W

(c) 4 W    

(d) 2 W

A torch bulb rated as 4.5 W, 1.5 V is connected as shown in the figure. The e.m.f. of the cell needed to make the bulb glow at full intensity is

(a) 4.5 V

(b) 1.5 V

(c) 2.67 V

(d) 13.5 V

The wavelength of emission line spectrum and absorption line spectrum of a substance are related as

(a) Absorption has larger value

(b) Absorption has smaller value

(c) They are equal

(d) No relation

A piece of wire of resistance 4 ohms is bent through 180°  at its mid point and the two halves are twisted together, then the resistance is

(a) 8 ohms

(b) 1 ohm

(c) 2 ohms

(d) 5 ohms

A current source sends a current $\text{I}-\text{i}_0\cos(\omega\text{t}).$ when connected across an unknown load, it gives a voltage output of $\text{v}=\text{v}_0\sin[\omega\text{t}+(\frac{\pi}{4})]$across that load. then the voltage across the current source may be brought in phase with the current through it by.
When charged particle enters-a uniform magnetic field, its K.E:

When the electron in the hydrogen atom jumps from 2nd orbit to 1st orbit, the wavelength of radiation emitted is 𝜆. When the electrons jump from 3rd orbit to 1st orbit, the wavelength of emitted radiation would be

(a)  

(b)

(c)

(d)

The focal length of a converging lens are fv and fr for violet and red light respectively:
  1. fv > fr
  2. fv - fr
  3. fv < fr
  4. Any of the three is possible depending on the value of the average refractive index $\mu$.