In the circuit shown in the figure, if the potential at point $A$ is taken to be zero, the potential at point $B$ is ................ $V$
AIPMT 2011, Medium
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Applying Kirchoff voltage law in the circuit as shown in the figure below.
$\therefore V_{A}+1+2(1)-2=V_{B} $
$0+1 =V_{B} \left(\because V_{A}=0 \mathrm{V}(\text { Given })\right) $
$V_{B} =+1 \mathrm{V}$
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