In the figure given below, the current passing through $6\,\Omega $ resistor is ........... $ampere$
Easy
Download our app for free and get started
(b) P.d. across the circuit $ = 1.2 \times \frac{{6 \times 4}}{{6 + 4}} = 2.88\,volt$
Current through $6\,ohm$ resistance $ = \frac{{2.88}}{6} = 0.48\,A$
Current through $6\,ohm$ resistance $ = \frac{{2.88}}{6} = 0.48\,A$
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1In a Wheatstone’s bridge all the four arms have equal resistance $R$. If the resistance of the galvanometer arm is also $R$, the equivalent resistance of the combination as seen by the battery isView Solution
- 2$A$ current passes through a wire of nonuniform cross section. Which of the following quantities are independent of the cross-section?View Solution
- 3View SolutionIn the below circuit the current in each resistance is
- 4Twelve resistors each of resistance $16 \,\Omega $ are connected in the circuit as shown. The net resistance between $AB$ (any two conjugate points of outer square) is ............... $\Omega$View Solution
- 5View SolutionAn energy source will supply a constant current into the load if its internal resistance is
- 6A copper wire has a square cross-section, $2.0\, mm$ on a side. It carries a current of $8\, A$ and the density of free electrons is $8 \times {10^{28}}\,{m^{ - 3}}$. The drift speed of electrons is equal toView Solution
- 7View SolutionThe lead wires should have
- 8The equivalent resistance between $A$ and $B$ as shown in figure is $........\,k\Omega$View Solution
- 9Resistances $R_1$ and $R_2$ each $60\,\Omega$ are connected in series as shown in figure. The Potential difference between $A$ and $B$ is kept $120$ volt. Then what ............. $V$ will be the reading of voltmeter connected between the point $C$ and $D$ if resistance of voltmeter is $120\,\Omega .$View Solution
- 10A meter bridge setup is shown in the figure. It is used to determine an unknown resistance $R$ using a given resistor of $15\,\Omega$. The galvanometer $(G)$ shows null deflection when tapping key is at $43\,cm$ mark from end $A$. If the end correction for end $A$ is $2\,cm$. then the determined value of $R$ will be__________ $\Omega$View Solution
