In the figure given below, the current passing through $6\,\Omega $ resistor is ........... $ampere$
A$0.40$
B$0.48$
C$0.72$
D$0.80$
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B$0.48$
b (b) P.d. across the circuit $ = 1.2 \times \frac{{6 \times 4}}{{6 + 4}} = 2.88\,volt$
Current through $6\,ohm$ resistance $ = \frac{{2.88}}{6} = 0.48\,A$
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