In the figure shown, battery $1$ has $\mathrm{emf}$ $= 6\, V$ and internal resistance $= 1 \,\Omega$. Battery $2$ has $\mathrm{emf}$ $= 2\,V$ and internal resistance $= 3\, \Omega$ . The wires have negligible resistance. What is the potential difference across the terminals of battery $2$ ? ................ $V$
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Battery $2$ is in changing mode

$I=\frac{6-2}{1+3}=1 A m p$

$V_{2}=E_{2}+I r_{2}=2+1 \times 3=5 V$

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