MCQ
In the Gabriel's phthalimide synthesis, phthalimide is treated first with
- ✓${C_2}{H_5}I/KOH$
- BEthanolic $Na$
- CEthanol and ${H_2}S{O_4}$
- DEther and $LiAl{H_4}$
✓
Answer
Correct option: A.
${C_2}{H_5}I/KOH$
a
Gabriel phthalimide is firstly treated with alcoholic Kor fo form potassium phthalimide which on further reaction with ethyl iodide gives Ne ethyl phthalimide, The product $N-$ethyl phthalimite is hydrolysed with dilute $H C$ lo form primary amine, ie. ethylamine. Th is reaction is known as Gabriel phthalimide synthesis.
Gabriel phthalimide is firstly treated with alcoholic Kor fo form potassium phthalimide which on further reaction with ethyl iodide gives Ne ethyl phthalimide, The product $N-$ethyl phthalimite is hydrolysed with dilute $H C$ lo form primary amine, ie. ethylamine. Th is reaction is known as Gabriel phthalimide synthesis.
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→$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
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{\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
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\end{array}$ ; Product $A$ is