In the Wheatstone's bridge (shown in figure) $X = Y$ and $A > B$. The direction of the current between ab will be
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In the part $c\, b\, d$,
${V_c} - {V_b} = {V_b} - {V_d}$ $ \Rightarrow $ ${V_b} = \frac{{{V_c} + {V_d}}}{2}$
In the part $c\, a\, d$
${V_c} - {V_a} > {V_a} - {V_d}$ $ \Rightarrow $ $\frac{{{V_c} + {V_d}}}{2} > {V_a}$ $ \Rightarrow $ ${V_b} > {V_a}$
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