MCQ
જો $a = i + j + k, b = i + j, c = i $ અને $(a\times b)\times c =\lambda \,\,a + \mu \,\,b$, તો $\lambda + \mu$ = ….
- ✓$0$
- B$1$
- C$2$
- D$3$
માગેલ $\,(a \times b) \times c = (c\,.\,a)b - (c\,.\,b)\,a = \mu \,b + \lambda a$
જ્યાં $\mu = c\,.\,a = 1,\,\,\lambda = - \,(c\,.\,b) = - \,1$ $ \Rightarrow \,\,\mu + \lambda = 1 - 1 = 0$
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$-\cos \left(\frac{3 \pi}{4}-\mathrm{x}\right))$ નો વિસ્તાર મેળવો.