MCQ
જો $P_n = cos^nx+ sin^nx $ તો $2P_6 - 3P_4 + 1 = ..... $
- A$2$
- B$3$
- C$1$
- ✓$0$
$ 2P_6 - 3 P_4 + 1$
$= 2 \left(cos^6x + sin^6x\right) - 3 \left(cos^4x + sin^4\right) + 1$
$= 2 \left[\left(cos^2x + sin^2x\right)^3 - 3 cos^2x sin^2x \left(cos^2x + sin^2x\right)\right]$$-3 \left[\left(cos^2x + sin^2x\right)^2 - 2cos^2x sin^2x\right]+1$
$= 2 (1 - 3 cos^2x sin^2x) - 3 (1 - 2 cos^2x sin^2x) +1$
$= 0$
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