Kinetic energy of a particle executing simple harmonic motion in straight line is $pv^2$ and potential energy is $qx^2$, where $v$ is speed at distance $x$ from the mean position. It time period is given by the expression
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$\mathrm{KE}=\mathrm{TE} \propto \mathrm{pA}^{2} \omega^{2}$
$\mathrm{PE}=\mathrm{TE} \propto \mathrm{q} \mathrm{A}^{2}$
$\mathrm{PA}^{2} / \omega^{2}=\mathrm{q} \mathrm{A}^{2}$
$\mathrm{T}=2 \pi \sqrt{\frac{p}{q}}$
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