MCQ
$\mathop {\lim }\limits_{x \to 0} \,\left( {\left[ {\frac{{100x}}{{\sin \,x}}} \right] + \left[ {\frac{{99\,\sin \,x}}{x}} \right]} \right)$ =
(જ્યાં $[.]$ એ મહત્તમ પૂર્ણાક વિધેય છે )
- A$197$
- ✓$198$
- C$199$
- Ddoes not exist
(જ્યાં $[.]$ એ મહત્તમ પૂર્ણાક વિધેય છે )
$\therefore\left[\frac{100 x}{\sin x}\right]=100$ and $\left[\frac{99 \sin x}{x}\right]=98$
$\therefore$ Ans is $198.$
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