Potentiometer wire of length $1 \,m$ is connected in series with $490\,\Omega $ resistance and $2\,V$ battery. If $0.2\, mV/cm $ is the potential gradient, then resistance of the potentiometer wire is ................ $\Omega$
Medium
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1The electric bulbs have tungsten filaments of same length. If one of them gives $60 \,watt$ and other $100\, watt$, thenView Solution
- 2Current of $4.8\,A$ is flowing through a conductor. The number of electrons per second will beView Solution
- 3In steady state the potential difference across the capacitor is $10\,\, V.$ Each resistance is of $3\,\Omega $. The cell is ideal. The $emf$ of the cell is .............. $\mathrm{V}$View Solution
- 4In the following circuit, $1 \,\Omega$ resistor dissipates power $P$. If the resistor is replaced by $9 \,\Omega$, the power dissipated in it isView Solution
- 5View SolutionThe following four wires are made of the same material and are at the same temperature. Which one of them has highest electrical resistance
- 6Seven resistances are connected as shown in the figure. The equivalent resistance between $A$ and $B$ is ............... $\Omega$View Solution
- 7In the circuit shown, the energy stored in the capacitor is $n\,\mu J$. The value of $n$ is ..............View Solution
- 8View SolutionCurrent provided by a battery is maximum when
- 9When a resistance of $2\,ohm$ is connected across the terminals of a cell, the current is $0.5$ amperes. When the resistance is increased to $5\, ohm$, the current is $0.25\, amperes$. The internal resistance of the cell is ............. $ohm$View Solution
- 10The heating coils rating at $220\, volt$ and producing $50\, cal/sec$ heat are available with the resistances $55\,\Omega $ , $110\,\Omega$ , $220\,\Omega $ and $440\,\Omega $. The heater of maximum power will be of............. $\Omega$View Solution