MCQ
Propan$-1-$ol can be prepared from propene by alcohol
- A${H_2}O/{H_2}S{O_4}$
- B$Hg{(OAc)_2}/{H_2}O$ followed by $NaB{H_4}$
- ✓${B_2}{H_6}$ followed by ${H_2}{O_2}$
- D$C{H_3}C{O_2}H/{H_2}S{O_4}$
$C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}OH$
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$\ln {k_t} = \ln {k_0} + \left( {\frac{{\ln \left( {\frac{5}{2}} \right)}}{{10}}} \right) \times t\left( {t \geqslant 0{}\,^0C} \right)$
$K_0$ =rate constant at $0\,^o C$ ; $k_t$ = rate constant at $t\,^o C$
Temperature coefficient of reaction, assuming that the rate constant increases same number of times on each $10\,^oC$ rise in temperature, is