Reading of ammeter in ampere for the following circuit is
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Applying Kirchhoffs law

for loop $ABCDEA:$ $2 i_{1}+2\left(i_{1}+i_{2}\right)=2 \Rightarrow 2 i_{1}+i_{2}=1 \ldots . .(1)$

for loop $HCDFGH:$ $2\left(i_{1}+i_{2}\right)+2 i_{2}=2 \Rightarrow i_{1}+2 i_{2}=1 \ldots . .(2)$

From $(1)$ and $(2),$ $i_{1}+2\left(1-2 i_{1}\right)=1$ or $-3 i_{1}=-1 \Rightarrow i_{1}=1 / 3 A$

and $i_{2}=1-2(1 / 3)=1 / 3 A$

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