Resistance of a wire at $0^{\circ} \mathrm{C}, 100^{\circ} \mathrm{C}$ and $t^{\circ} \mathrm{C}$ is found to be $10 \Omega, 10.2 \Omega$ and $10.95 \Omega$ respectively. The temperature $t$ in Kelvin scale is $\qquad$
JEE MAIN 2024, Diffcult
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$\mathrm{R}=\mathrm{R}_0(1+\alpha \Delta \mathrm{T})$
$\frac{\Delta \mathrm{R}}{\mathrm{R}_0}=\alpha \Delta \mathrm{T}$
Case-I
$0{ }^{\circ} \mathrm{C} \rightarrow 100^{\circ} \mathrm{C}$
$\frac{10.2-10}{10}=\alpha(100-0)$
Case-II
$0^{\circ} \mathrm{C} \rightarrow t^{\circ} \mathrm{C}$
$\frac{10.95-10}{10}=\alpha(t-0)$
$\Rightarrow \frac{t}{100}=\frac{0.95}{0.2}=475^{\circ} \mathrm{C}$
$t=475+273=748 \mathrm{~K}$
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