Resistors of $1$, $2$, $ohm$ are connected in the form of a triangle. If a $1.5\, volt$ cell of negligible internal resistance is connected across $3\, ohm$ resistor, the current flowing through this resistance will be ................ $amp$
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${i_1} + {i_2} = \frac{{1.5}}{{3/2}} = 1\,amp$
$\frac{{{i_1}}}{{{i_2}}} = \frac{3}{3}$ $ \Rightarrow $ ${i_1} = {i_2}$
${i_2} = 0.5\,A = {i_1}$
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