Question
State Faraday's second law of electrolysis.

Answer

Faraday's second law: According to this law when same quantity of electricity is passed through solution of different electrolytes, the amount of substance liberated at the electrodes is proportional to their equivalent masses.
If $m_{1}$ and $m_{2}$ are the masses of metal deposited by passing same quantity of electricity and $E_{1}$ and $E_{2}$ are their equivalent masses respectively then $\frac{m_{1}}{m_{2}} = \frac{E_{1}}{E_{2}}$

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