MCQ
Sugar of lead is
- A$2PbS{O_4}.PbO$
- ✓${(C{H_3}COO)_2}Pb$
- C$PbC{O_3}$
- D$PbC{O_3}.Pb{(OH)_2}$
✓
Answer
Correct option: B.
${(C{H_3}COO)_2}Pb$
b
(b) Sugar of lead ${(C{H_3}COO)_2}Pb$ $⇒$ lead acetate
(b) Sugar of lead ${(C{H_3}COO)_2}Pb$ $⇒$ lead acetate
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Given below are two statements: one is labelled as Assertion $(A)$ and the other is labelled as Reason $(R)$.
→Assertion $(A)$: Cis form of alkene is found to be more polar than the trans form
Reason $(R)$: Dipole moment of trans isomer of $2$-butene is zero.
In the light of the above statements, choose the correct answer from the options given below :
$18\, L$ mixture of $N_2$ and $H_2$ gives maximum $6\, L$ of $NH_3$ at same temperature and pressure then what will be ratio of $N_2$ and $H_2$ initially taken ?
→For the chemical reaction $3X(g) + Y(g) \to X_3Y(g)$ the amount of $X_3Y$ at equilibrium is affected by
→The addition of $HBr$ is easiest with
→$Ce - 58$ is a member of
→Which one of the following pairs of gases contains the same number of molecules
The $IUPAC$ name of compound is
→Which of the following alkene on catalytic hydrogenation given cis and trans- isomer?
Given below are two statement: one is labelled as Assertion $A$ and the other is labelled as Reason $R$
→Assertion $A:$ $5 f$ electrons can participate in bonding to a far greater extent than $4 f$ electrons
Reason $R:$ $5 f$ orbitals are not as buried as $4 f$ orbitals
In the light of the above statements, choose the correct answer from the options given below
In the given reaction
→$C{H_3}C{H_2}CH = CHC{H_3}$ $\xrightarrow{X}C{H_3}C{H_2}COOH\, + \,C{H_3}COOH$
The $X$ is