MCQ
The angular speed of seconds needle in a mechanical watch is
- ✓$\frac{\pi }{{30}}\,rad/s$
- B$2\pi \,rad/s$
- C$\pi \,rad/s$
- D$\frac{{60}}{\pi }\,rad/s$
✓
Answer
Correct option: A.
$\frac{\pi }{{30}}\,rad/s$
a
(a)$\omega = \frac{{2\pi }}{T} = \frac{{2\pi }}{{60}} = \frac{\pi }{{30}}\,rad/s$
(a)$\omega = \frac{{2\pi }}{T} = \frac{{2\pi }}{{60}} = \frac{\pi }{{30}}\,rad/s$
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